In an experiment to determine the solubility of PbCl2 in water, it was found that a maximum of 0.45 g of the salt would dissolve in 100 mL of water at 25°C.
(A) Calculate the solubility of PbCl2 in its saturated solution in moles per litre. (Molar mass of PbCl2 = 278.10 g mol-1)
(B) Calculate the Ksp for PbCl2 in water at 25°C.
(C)Comment on the solubility of PbCl2 in a solution of NaCl at 25°C.
Answers for A= 0.016 mol L-1 and B = 1.7x10^-5
Could you please show working :)
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