Question

One of the coal-burning units produces 355 MW . How many metric tons (1 metric ton = 1×106 g ) of coal per hour are required to operate this unit at its peak output if the enthalpy of combustion of coal is 29.0×103 kJ⋅kg−1 ?

Express your answer with the appropriate units.

Show all steps and conversions

Answer 1

power = 355 MW = 355 x 10^6 W

           = 3.55 x10^8 W

          = 3.55 x 10^8 J / sec

         = 3.55 x 10^5 kJ / sec

         = 3.55 x 10^5 x 3600 kJ / hour

          = 1.28 x 10^9 kJ / hour

H = 29.0 x 10^3 kJ / kg

weight=    power / H

           =   1.28 x 10^9 kJ / hour / 29.0 x 10^3 kJ / kg

            = 44069 kg / hour

           = 44 metric ton / hour