Question

One of the coal-burning units produces 355 MW . How many metric tons (1 metric ton = 1×106 g ) of coal per hour are required to operate this unit at its peak output if the enthalpy of combustion of coal is 29.0×103 kJ⋅kg−1 ?

Express your answer with the appropriate units.

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Answer #1

power = 355 MW = 355 x 10^6 W

= 3.55 x10^8 W

= 3.55 x 10^8 J / sec

= 3.55 x 10^5 kJ / sec

= 3.55 x 10^5 x 3600 kJ / hour

= 1.28 x 10^9 kJ / hour

H = 29.0 x 10^3 kJ / kg

weight= power / H

= 1.28 x 10^9 kJ / hour / 29.0 x 10^3 kJ / kg

= 44069 kg / hour

**= 44 metric ton / hour**

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