Question

4NH3+ 5O2 --> 4NO + 6H20

a. How many grams of O2 are needed to react completely with 5.5 g of NH3?

b. How many grams of H2O are produced from 5.44g O2?

Answer 1

(a)

4NH3+ 5O2 --> 4NO + 6H20

As per te stoichiometry of the above reaction 4 moles or 4 X 17 = 68g of NH3 are peroduced by 5 moles or 5 X 32g = 160g of O2.

Thus

68g of NH3 = 160g of O2.

1g of NH3 = 160g / 68 = 2.35g of O2

It means 1g of NH3 will be produced by 2.35g of O2.

Therefore 5.5g of NH3 will be produced from 2.35 X 5.5 = 12.94g of O2

Thus 5.5g of NH3 will be produced from 12.94g of O2.

(b)

5 mol or 160g of O2 produce 6 mol or 6 X 18 = 108g of water.

Thus equation becomes

160g of O2 = 108g of water.

or 1g of O2 = 108 / 160 = 0.675g of H2O

It means 1g of O2 produce 0.675g of H2O

Therefore 5.5g of O2 = 0.675 X 5.5 = 3.71g of H2O

It means 3.71 g of H2O are prodeuced by 5.5f of O2.