Question

Calculate the shortest wavelength of the electromagnetic radiation emitted by the hydrogen atom in undergoing a transition from the n = 6 level

Answer 1

shortest wavelength will be emitted when there is largest energy difference because

E = h*c/wavelength

Energy difference will be maximum when electron return to ground state

Here photon will be emitted

1/wavelength = R* (1/nf^2 - 1/ni^2)

R is Rydberg constant. R = 1.097*10^7

1/wavelength = R* (1/nf^2 - 1/ni^2)

1/wavelength = 1.097*10^7* (1/1^2 - 1/6^2)

wavelength = 9.376*10^-8 m

Answer: 9.38*10^-8 m