Provide the complete symbol for the particle indicated by the question mark needed to balance the following nuclear equation.
a) 14N + ? -> 17O + 1P
b) 249Cf + 18O -> 263Sg + ?
c) ? + α -> 243Bk + n
d) 239Pu + n -> 140Sb + ? + 4n
e) 235U + n -> 132Sn + 3n
f) 241Am -> α + ?
g) 136La -> ? + β+
h) 27Al + 2H -> ? + 28Al
To balance the nuclear reaction both the mass number as well as the atomic number will balance means the total of the mass number and atomic number of reactants are same as product.
a) 14N + ? -> 17O + 1P
14N + ? -> 17O + 1P
Assume the bombarding particle is X
14N + X -> 17O + 1P
The mass number of unknown product:
7+ A = 8+1
A= 2
The atomic number of unknown product:
14+ z = 17+1
z= 4
thus the particle is 2 He 4.
7-N-14 + 2-He-4 ---> 8-O-17 + 1-H-1
b) 249Cf + 18O -> 263Sg + ?
Assume the product particle is X
249+ 18= 263+A
A= 4
98+8= 106+Z
Z = 2
249Cf + 18O -> 263Sg + 4 He
c) ? + α -> 243Bk + n
Assume the particle is X
X+ α -> 243Bk + n
The mass number of unknown product:
4+ A = 243+1
A= 240
The atomic number of unknown product:
2+ z = 97+0
z=9 5
thus the particle is 240 Am95.
240 Am+ α -> 243Bk + n
d) 239Pu + n -> 140Sb + ? + 4n
Assume the product particle is X
239+ 1= 140+A+4*1
A= 96
94+0= 51+Z+ 0
Z = 43
239Pu + n -> 140Sb + 96Tc+ 4n
Get Answers For Free
Most questions answered within 1 hours.