Question

Consider a mixture of air and gasoline vapor in a cylinder with a piston. The original...

Consider a mixture of air and gasoline vapor in a cylinder with a piston. The original volume is 30. cm3. If the combustion of this mixture releases 943 J of energy, to what volume will the gases expand against a constant pressure of 632 torr if all the energy of combustion is converted into work to push back the piston?

Homework Answers

Answer #1

Original Volume = 30 cm3 = 30x10-6 m3

P = Pressure = 632 Torr

Since 1 torr = 133.3 Pa

So, P = 632x133.3 =84245.6 Pa

w (work done) = Energy released from the combustion of mixture of air and gasoline = -943J (negative because work done by the system on the surroundings)

since the work done is given by the equation:

w = -P∆V

∆V = -w/P

V2-V1 = -w/P (V2 is final volume and V1 is initial volume)

V2- 30x10-6    = -(-943)/84245.6

V2 =30x10-6 +.0111934

= .011223m3

The gases expand to a volume of .011223m3.

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