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A home melting pot is used for a metal casting hobby. At the end of a...

A home melting pot is used for a metal casting hobby. At the end of a work period, the pot contains 608 grams of lead at 439°C. How much energy will be released as the molten metal cools, solidifies, and cools further to room temperature, 22°C? Data for lead at 1 atm: Melting point = 328°C Specific heat liquid = 0.138 J/g ⋅ °C Specific heat solid = 0.130 J/g ⋅ °C Heat of fusion = 23.0 J/g __J

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Answer #1

Ti = 439.0 oC

Tf = 22.0 oC

Cl = 0.138 J/g.oC

Heat released to convert liquid from 439.0 oC to 328.0 oC

Q1 = m*Cl*(Ti-Tf)

= 608 g * 0.138 J/g.oC *(439-328) oC

= 9313.344 J

Lf = 23.0 J/g

Heat released to convert liquid to solid at 328.0 oC

Q2 = m*Lf

= 608.0g *23.0 J/g

= 13984 J

Cs = 0.13 J/g.oC

Heat released to convert solid from 328.0 oC to 22.0 oC

Q3 = m*Cs*(Ti-Tf)

= 608 g * 0.13 J/g.oC *(328-22) oC

= 24186.24 J

Total heat released = Q1 + Q2 + Q3

= 9313.344 J + 13984 J + 24186.24 J

= 47484 J

= 47.5 KJ

Answer: 47.5 KJ

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