Question

If 38.17 mL of 0.1072 M NaOH is required to titrate a 15.00 mL sample of sulfuric acid, what is the molarity of the acid?

Answer 1

The balanced equation is

2NaOH + H2SO4 ----- > Na2SO4 + 2H2O

Number of moles of NaOH = molarity * volume of solution in L

Number of moles of NaOH = 0.1072 * 0.03817 = 0.00409 mole

From the balanced equation we can say that

2 mole of NaOH requires 1 mole of H2SO4 so

0.00409 mole of NaOH will require 0.00205 mole of H2SO4

molarity of H2SO4 = number of moles of H2SO4 / volume of solution in L

molarity of H2SO4 = 0.00205 / 0.015 = 0.137 M

Therefore, the molarity is 0.137 M