Question

Rank the following salts in order of increasing molar solubility. Salt Ksp AgSCN 1.0 × 10–12...

Rank the following salts in order of increasing molar solubility. Salt Ksp AgSCN 1.0 × 10–12 Ag2CrO4 1.1 × 10–12 Ag3PO4 1.0 × 10–16

Homework Answers

Answer #1

1)

The salt dissolves as:

AgSCN <----> Ag+ + SCN-

   s s

Ksp = [Ag+][SCN-]

1*10^-12=(s)*(s)

1*10^-12= 1(s)^2

s = 1*10^-6 M

2)

The salt dissolves as:

Ag2CrO4 <----> 2 Ag+ + CrO42-

   2s s

Ksp = [Ag+]^2[CrO42-]

1.1*10^-12=(2s)^2*(s)

1.1*10^-12= 4(s)^3

s = 6.503*10^-5 M

3)

The salt dissolves as:

Ag3PO4 <----> 3 Ag+ + PO43-

   3s s

Ksp = [Ag+]^3[PO43-]

1*10^-16=(3s)^3*(s)

1*10^-16= 27(s)^4

s = 4.387*10^-5 M

The compounds in increasing order of solubility are:

AgSCN whose solubility is 1*10^-6 M

Ag3PO4 whose solubility is 4.387*10^-5 M

Ag2CrO4 whose solubility is 6.503*10^-5 M

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Rank the following salts in order of increasing molar solubility BaSO4 = 1.1 x 10-10 AgCl...
Rank the following salts in order of increasing molar solubility BaSO4 = 1.1 x 10-10 AgCl = 1.8 x 10-10 BaCO3 = 9.1 x 10-9 CdS = 8 x 10-27 PbSO4 = 1.8 x 10-8 Please explain, thanks!
Calculate the molar solubility of Ag2CrO4 (Ksp = 1.1 × 10-12) at 25 °C in various...
Calculate the molar solubility of Ag2CrO4 (Ksp = 1.1 × 10-12) at 25 °C in various aqueous solutions. Calculate the solubility in 0.249 M AgNO3 Calculate the solubility in 0.134 M Na2CrO4
Calculate the molar solubility of Ag2CrO4 (Ksp = 1.1 × 10-12) at 25 °C in various...
Calculate the molar solubility of Ag2CrO4 (Ksp = 1.1 × 10-12) at 25 °C in various aqueous solutions. A)Calculate the solubility in 0.200 M AgNO3 B)Calculate the solubility in 0.200 M Na2CrO4
What is the Ksp for the following and arrange these in order of their increasing molar...
What is the Ksp for the following and arrange these in order of their increasing molar solubility. Show all work. a. PbCrO4 b. Zn(OH)2 c. Ag2CO3 d. Ag3PO4 Thank you! It will be greatly appreciated
Rank the following salts from least to most molar solubility: BiI Ksp = 7.7x10-19 Cd3(AsO4)2 Ksp...
Rank the following salts from least to most molar solubility: BiI Ksp = 7.7x10-19 Cd3(AsO4)2 Ksp = 2.2x10-33 AlPO4 Ksp = 9.8x10-21 CaSO4 Ksp = 4.9x10-5 I know the answer, although I don't know how
Which of the following salts has the lowest molar solubility? Show work. A.) SrCO3 (Ksp =...
Which of the following salts has the lowest molar solubility? Show work. A.) SrCO3 (Ksp = 9.3 x 10^-10) B.) MnS (Ksp = 2.5 x 10^-10) C.) BaF2 (Ksp = 1 x 10^-6) D.) BaSO4 (Ksp = 1.1 x 10^-10) E.) AgCl (Ksp = 1.8 x 10^-10)
I had 2,3,5,4,1 but it was wrong. Rank the following five salts in order of decreasing...
I had 2,3,5,4,1 but it was wrong. Rank the following five salts in order of decreasing solubility, in terms of mass per unit volume.   (The most soluble gets rank 1, the least soluble gets rank 5.) 1 2 3 4 5  Ag3PO4     (Ksp = 1.80×10-18) 1 2 3 4 5  Ag2CO3     (Ksp = 8.10×10-12) 1 2 3 4 5  Ca5(PO4)3OH     (Ksp = 6.80×10-37) 1 2 3 4 5  Sr3(PO4)2     (Ksp = 1.00×10-31) 1 2 3 4 5  AgCl     (Ksp = 1.60×10-10)
Use the Ksp values to calculate the molar solubility of each of the following compounds in...
Use the Ksp values to calculate the molar solubility of each of the following compounds in pure water. MX (Ksp = 1.47×10−38) Ag2CrO4 (Ksp = 1.12×10−12)
Ksp for Ag2CrO4=5.4x10^-12. Calc molar solubility of Ag2CrO4 in 0.0050M K2CrO4
Ksp for Ag2CrO4=5.4x10^-12. Calc molar solubility of Ag2CrO4 in 0.0050M K2CrO4
calculate the molar solubility of the following salts under specific conditions: Calcium carbonate(CaCO3) in water [Ksp=...
calculate the molar solubility of the following salts under specific conditions: Calcium carbonate(CaCO3) in water [Ksp= 4.5*10^-9] Calcium fluoride (CaF2) in water [Ksp= 3.2*10^-11] Zinc (11) hydroxide (Zn(OH)2) in a solution of pH= 7.50 [Ksp=3.0*10^-16]
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT