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Given the following values for HC2O4^- (Ka=6.4E-5 and kb=1.7E-13) which reaction from above is favored? Would...

Given the following values for HC2O4^- (Ka=6.4E-5 and kb=1.7E-13) which reaction from above is favored? Would a salt solution of NaHC2O4 be acidic basic or neutral?

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Answer #1

NaHC2O4 dissociates to Na+ + HC2O4- so the salt is an acidic salt
The Ka value of HC2O4- = 6.1x10-5 which greater than Kb and 1x10-7 which would be the dissociation constant of H+ from water.

Therefore, HC2O4- = acidic
Assume that we have 1M HC2O4-
Ka = 6.1x10-5 = [H+][C2O42-] / [HC2O4- ]
6.1x10-5 = x2 / 1-x
x2 + 6.1x10-5x - 6.1x10-5 = 0
solving this quadratic equation
x = [H+] = 0.0078 M ,

pH=-log[H+]= -log[0.0078]=2.1,

pH=2.1, So HC2O4- is Acidic

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