What is the concentration in ppm Mg for a solution that is 5.0 x 10-4 M in MgCl2? please show calculations
Molarity = no. of mole of solute / volume of solvent in L
Molarity represented by mole/liter
Given molarity; M = 5.0 x 10-4 M = 5.0 x 10-4 moles/liter
ppm = parts per millian
conversion of mole/Liter to ppm can be represented by
ppm = (moles/liter) x 1000 x molecular weight
ppm = 5.0 x 10-4 x 1000 x 95.205 = 47.6025 ppm
concentration of MgCl2 = 47.6025 ppm
Percentage of Mg in MgCl2= (24.305/95.205) x 100 = 25.53 %
concentration of Mg = 47.6025 x (0.2553) = 12.1525 ppm of Mg
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