Photons with a wavelength of 353 nm have just enough energy to rupture the C—Cl bond in CF3Cl. What is the C—Cl bond dissociation energy?
wavelength = 353 nm = 3.53*10^-7 m
Find energy of 1 photon first
we have below equation to be used:
Energy = Planck constant*speed of light/wavelength
=(6.626*10^-34 J.s)*(3.0*10^8 m/s)/(3.53*10^-7 m)
= 5.631*10^-19 J
This is energy of 1 photon
Energy of 1 mol = energy of 1 photon * Avogadro's number
= 5.631*10^-19*6.022*10^23 J/mol
= 3.391*10^5 J/mol
= 3.39*10^2 KJ/mol
Answer: 3.39*10^2 KJ/mol
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