Question

Dinitrogen oxide (N2O), laughing gas, is used by dentists as an
anesthetic. If a 20.0 L tank of laughing gas has a pressure of
2.64×103 mmHg, how many moles of N2O in the tank?

Answer #1

PV = nRT

where, P = 2.64*10^3 mmHg = 3.473684 atm

V = 20.0 L

R = 0.08206 L.atm/ mol.K

T = 298.15 K

Moles of N2O, n = (PV/RT)

= ((3.473684 * 20.0) / (0.08206 * 298.15))

= 2.84 moles

Number of moles N2O = 2.84 moles

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