An expanding gas does 143 J of work on its surroundings at a constant pressure of 1.04 atm. If the gas initially occupied 68.0 mL, what is the final volume of the gas?
W = 143J
1L-atm = 101.3J
101.3J = 1L-atm
143J = 1L-atm*143J/101.3J = 1.412 L-atm
V1 = 68ml = 0.068L
W =I -PV I
W = P(V2-V1)
1.412 = 1.04*(V2-0.068)
V2-0.068 = 1.412/1.04
V2 -0.068 = 1.3576
V2 = 1.3576+0.068 = 1.4256L = 1425.6ml>>>>answer
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