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A scientist measures the standard enthalpy change for this reaction to be 163.2 kJ/mol. CaCO3(s)CaO(s) +...

A scientist measures the standard enthalpy change for this reaction to be 163.2 kJ/mol. CaCO3(s)CaO(s) + CO2(g) Based on this value and the standard formation enthalpies for the other substances, the standard formation enthalpy of CO2(g) is ____ kJ/mol.

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Answer #1

CaCO3(s)----->CaO(s) + CO2(g)
H0rxn = [H0f(CaO) + H0f(CO2)] - [H0f(CaCO3)]

163.2 = [-635.09 + H0f(CO2)] - [-1206.92]

163.2 = 571.83 + H0f(CO2)  

H0f(CO2)   = - 408.63 KJ/mol

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