IF HA IS A WEAK ACID, WHICK EQUILIBRIUM CORRESPONDS TO THE ACID EQUILIBRIUM CONSTANT Ka for Ha?
a. HA (aq) + H2O (l)<--->H2A+ (aq) + OH- (aq)
b. A- (aq) + H3O+ (aq)<---> HA (aq) + H2O (l)
c. HA (aq) + OH-(aq)<---> H2O (l) + H+ (aq)
d. A- (aq) +H2 O (l)<---> HA (aq) + OH- (aq)
e. A- (aq) + OH- (aq)<---> HOA2- (aq)
Given, HA is a weak acid,
The equilibrium reaction for HA is,
HA(aq) + H2O(l) A-(aq) + H3O+(aq)
Since H3O+ species is present in the equilibrium reaction, We write the Acid equilibrium constant(Ka).
If we reverse the reaction,
A-(aq) + H3O+(aq) HA(aq) + H2O(l)
The Acid equilibrium constant value will inverse of the Ka but the value is the acid equilibrium constant.
Thus, Option (B) A-(aq) + H3O+(aq) HA(aq) + H2O(l) is the acid equilibrium constant for HA.
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