Question

How many grams of BaSO4 will produced when 2.1 moles of Cr(SO4)3 react?

Answer 1

Cr(SO4)3 has 3 SO42-

So,

1 mol of Cr(SO4)3 forms 3 moles of BaSO4

So,

moles of BaSO4 = 3*mol of Cr(SO4)3

= 3*2.1 mol

= 6.3 mol

Molar mass of BaSO4 = 1*MM(Ba) + 1*MM(S) + 4*MM(O)

= 1*137.3 + 1*32.07 + 4*16.0

= 233.37 g/mol

we have below equation to be used:

mass of BaSO4,

m = number of mol * molar mass

= 6.3 mol * 233.37 g/mol

= 1470 g

Answer: 1470 g