Question

Part A For the reaction Part A 3A(g)+3B(g)⇌C(g) Kc = 82.6 at a temperature of 15 ∘C . Calculate the value of Kp.

Part B For the reaction X(g)+3Y(g)⇌2Z(g) Kp = 3.93×10−2 at a temperature of 183 ∘C . Calculate the value of Kc.

Pleasse help :(

Answer 1

A)

T= 15.0 oC

= (15.0+273) K

= 288 K

delta n = number of gaseous molecule in product - number of gaseous molecule in reactant

delta n = -5

Kp= Kc (RT)^delta n

Kp = 82.6*(0.0821*288.0)^(-5)

Kp = 1.12*10^-5

Answer: 1.12*10^-5

B)

T= 183.0 oC

= (183.0+273) K

= 456 K

delta n = number of gaseous molecule in product - number of gaseous molecule in reactant

delta n = -2

Kp= Kc (RT)^deltan

0.0393 = Kc *(0.0821*456.0)^(-2)

Kc = 55.1

Answer: 55.1