a 100 mL buffer solution containing 0.25 M CH3COOH and 0.15 M CH3COONa is placed into a volumetric flask and diluted to 250 mL with water.
a) Calculate the pH of the initial solution (when the volume was 100 mL)
b) Calculate the pH of the final solution, after dilution (when the volume is 250 mL)
What can you conclude?
= 4.75 + log 0.15/0.25
= 4.75 + log 15 – log25
= 4.75 + 1.1761 – 1.3979
= 4.53
[CH3COONa] = 100 x 0.15/250
[CH3COOH] = 100 x 0.25/250
pH = pKa + log [CH3COONa]/[CH3COOH]
= 4.75 + log 15 – log25
= 4.75 + 1.1761 – 1.3979
= 4.53
Conclusion: There is no effect of dilution on the pH of a buffer system
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