Question

Methane molecules (CH4) moving in air have an average velocity of 684 m/s. What is the kinetic energy of 1.00 mol of methane molecules in air?

11.0 J |

5.49 x 103 J |

5.49 J |

3.75 x 106 J |

3.75 x 103 J |

Answer #1

KE = 1/2 mv^2

v = 684m/s

mass of CH4 = no of moles * gram molar mass

= 1*16 = 16g = 16*10^-3 kg = 0.016Kg

KE = 1/2*(0.016)*(684)^2

= 7485.7/2 = 3742J

= 3.72*10^3 J

3.75 x 10^3 J >>>>answer

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