Question

5.Calculate the cell potential: Pb(s) | H2SO4 (4.0 M) || H2SO4(s) | PbO2

Answer 1

cell potential: Reduction Potentials of cathode -Reduction Potentials of anode

cell potential: Reduction Potentials of PbO₂--- Reduction Potentials of Pb

cell potential:1.69-(-0.13)

cell potential:1.82V

ranode (porous Pb): Pb(s) + HSO4 - (aq) X PbSO4(s) + H+ + 2e

cathode (PbO2): PbO2(s) + 3H+ (aq) + HSO4 - (aq) + 2e- X PbSO4(s) + 2H2O(l)

Ecell = 2.0 V

If the open circuit voltage of AGM cells is significantly higher than 2.093 volts, or 12.56 V for a 12 V battery, then they have a higher acid content than a flooded cell; while this is normal for an AGM battery, it is not desirable for long life.