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Continue and balance the following redox equation: (provide half-reactions) (NH4)2Cr2)7 -> Be + H2O2 + KOH...

Continue and balance the following redox equation: (provide half-reactions)

(NH4)2Cr2)7 ->

Be + H2O2 + KOH ->

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Answer #1

The Redox Reaction of   is given in the following-

In the 2nd case,there is no significant reaction known of Beryllium reacting with KOH and Hydrogen peroxide.You may check the reaction,there is a potential reaction between KOH and H2O2 which is a Decomposition reaction and not a redox reaction-

hope this helps!

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