Question

In the following reaction, how many grams of sodium sulfate, Na2SO4, will be produced from 88.3 g of sodium hydroxide, NaOH?

2NaOH + H2SO4 --> Na2SO4 + 2H2O

Answer 1

According to given balanced chemical reaction equation 2 mol NaOH reacts with 1 mol H₂SO₄ and produces 1 mol Na₂SO₄.

moles in 88.3 g of sodium hydroxide = 88.3 g / 39.997 g/mol = 2.20766557492 moles

moles Na₂SO₄ formed = 2.20766557492 moles / 2 = 1.10383278746 moles

convert this moles to mass (amount) = moles Na₂SO₄ x molar mass of Na₂SO₄

grams of Na₂SO₄ produced = 1.10383278746 mol x 142.04 g/mol = 156.788409131 g

grams of Na₂SO₄ produced = 157 grams (3 sig fig)

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