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Question 12 Kp=2.2x106 at 298K 2COF2(gas)<=====>CO2(gas)+CF4(gas) The reaction below has an equilibrium constant Kp=2.2x106 at 298k...

Question 12

Kp=2.2x106 at 298K

2COF2(gas)<=====>CO2(gas)+CF4(gas)

The reaction below has an equilibrium constant Kp=2.2x106 at 298k

2COF2(gas)<======>CO2(gas)+CF4(gas)

A. Calculate kp for the reaction below

4COF2(gas)<=====>2CO2(gas)+2CF4(gas)

B. Calculate Kp for reaction below.

2/3COF2(gas)<=====>1/3CO2(gas)+1/3CF4(gas)

C. Calculate Kp for the reaction below

2CO2(gas)+2CF4(gas)<=====>4COF2(gas)

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Homework Answers

Answer #1

A. Calculate kp for the reaction below

4COF2(gas)<=====>2CO2(gas)+2CF4(gas)


Kp1 = (Kp)^2

      = (2.2*10^6)^2

      = 4.84*10^12

B. Calculate Kp for reaction below.

2/3COF2(gas)<=====>1/3CO2(gas)+1/3CF4(gas)

Kp1 = (Kp)^2/3

      = (2.2*10^6)^(2/3)

     = 1.69*10^4


C. Calculate Kp for the reaction below

2CO2(gas)+2CF4(gas)<=====>4COF2(gas)

Kp1 = (1/Kp)^2

      = (1/(2.2*10^6))^2

      = 2.07*10^-13

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