Iron hydroxide will be formed by the reaction of iron(II) chloride with lithium hydroxide, according to the chemical equation shown. FeCl2 (aq) + 2 LiOH (aq) → Fe(OH)2 (s) + 2 LiCl (aq) What volume of 0.223-M LiOH (aq) will be required to produce 1.00 g Fe(OH)2 (s)?
Solution:- The given balanced equation is...
FeCl2(aq) + 2LiOH(aq) -----> Fe(OH)2(s) + 2LiCl(aq)
There is 1:2 between Fe(OH)2 and LiOH. First of all we would convert the given grams of Fe(OH)2 to moles and then using mol ratio we would calculate the moles of LiOH and finally using the given molarity the volume is calculated. The calculations would be done as...
1.00 g Fe(OH)2 x (1mol/89.86 g) x (2mol LiOH/1 mol Fe(OH)2) x (1L/0.223 mol) = 0.0998 L or 99.8 mL.
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