The rate law for the reaction between catalase and hydrogen peroxide can be written as Rate = k [H2O2]x [catalase]y. A catalase solution of unknown, but constant concentration is prepared. Can the partial order with respect to the peroxide (x) be found using this catalase solution? If so, how would you do it? Describe in detail the steps you would take or show a calculation.
Yes, we can get this
we can apply the initial rate law, in which we use the same catalase concentration and we vary the [H2O2] concnetration, we record the rate of reaction ( initial)
In order to calculate the rate law expression for a A+B reaction, we need to apply Initial Rates Method.
Note that the generic formula goes as follows:
r = k [A]^a [B]^b
Note that if we got at least 3 sets of point, in which we have A and B constant, then we could use:
r1 / r2 = (k1 [A]1^a [B]1^b) / (k2 [A]2^a [B]2^b)
If we assume K1 and K2 are constant, then K1= K2 cancel each other
r1 / r2 = ([A]1^a [B]1^b) / ( [A]2^a [B]2^b)
Then, order according to [A] and [B]
r1 / r2 = ([A]1/[A2])^a * ([B]1/[B]2)^b
If we get two points in which A1 = A2, then we could get B, and vise versa for A...
simply
substitute rate reactions
note that ([B]1/[B]2)^b --> catalse, will be always constant, or 1
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