Question

The pressure gauge of a steel cylinder of methane gas () reads 400 psi. The cylinder has a volume of 1.10 L and is at a temperature of 35.0°C. How many grams of methane does the cylinder contain? g

Answer #1

**Solution :-**

400 psi * 1atm / 14.7 psi = 27.21 atm

Temperature = 35 C +273 = 308 K

volume = 1.10 L

now using the ideal gas law equation lets calculate the moles of the methane

PV= nRT

PY/Rt =n

27.21 atm * 1.10 L / 0.08206 L atm per mol K * 308 K =n

1.184 mol = n

now lets convert the moles of the methane to its mass

mass= moles * molar mass

mass of methane = 1.184 mol * 16.04 g per mol

mass of methane = 19.0 g methane

so the mass of methane gas present is 19.0 g

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