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A 10.0 L container of NH3 gas at 25.8°C and 0.85 atm, is heated to 70.4°C...

A 10.0 L container of NH3 gas at 25.8°C and 0.85 atm, is heated to 70.4°C and a pressure of 1.35 atm. Calculate the new volume.

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Homework Answers

Answer #1

We know

PV= nRT

PV/T = nR = const

where R is Rydbergs const and n is no of moles of gas which would remain same after the new volume is achieved in container,

We would equate P1V1/T1 = P2V2/T2 (equation i)

P1 = 0.85 atm , P2 = 1.35 atm

T1 = 25.8C = 25.8+273 K= 298.8K , T2 = 70.4 C = 70.4 + 273 K = 343.4K

V1 = 10L

Put these values in eq i

0.85 atm*10L/298.8 K = 1.35 atm*V2/343.4 K

0.0284 atmL/K = 1.35 atm*V2/343.4K

V2 = (0.0284 atmL/K )*(343.4K/1.35 atm)

V2 = 7.23 L

Hence new volume is 7.23 L.

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