A cylinder if fitted with a floating piston oriented horizontally (the air is the system and by having a floating piston it maintains constant pressure). It contains 24.5 L of air at 25.0C and 1 bar pressure. The system is then heated to 250.0C. Air can be considered a diatomic gas and therefore would have a Cv = 5R/2, where R is the ideal gas constant. Also for gases Cp = Cv +R. How much work was done (in J) and how much heat was transferred?
if constant pressure, then
P1 = P2
1 bar = P2
At constant P
Q = dH is true
dH = n*Cp*dT
get n
n = PV/(RT) = 1*24.5/(0.08314*295) = 0.99892 mol
Cp = Cv + R = 5/2*R + R = 7/2R = 7/2*8.314 = 29.099 J/molK
Q = dH = n*Cp*(/Tf-Ti) = (0.99892)(29.099)(250-25)
Q = 6540.203 J
b)
if =P constant
W = -P*(Vf-Vi)
Vi = 24.5 L
Vf = from
V1/T1 = V2/T2
Vf = (250+273)/(25+273) * 24.5 = 42.998 = 43 L
P = 1 bar = 10^5 Pa 1 m3 = 10^3 L
W = -(1*10^5)(43-24.5)*10^-3
W = -1850 J = -1.85 kJ
W = - 1850 J = -1.85 kJ
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