Question

What volume (mL) of 7.48 × 10 -2 M perchloric acid can be neutralized with 115 mL of 0.244 M sodium hydroxide?

Answer 1

the balanced equation of reaction is

HCLO4+NAOH------>NACLO4+H2O

so to neutralise one mole of perchloric acid we need one mole of sodium hydroxide

we know number of moles =molarity*volume in litres

moles=M*V(L)

equating moles of both

moles of HCLO4 has to be equal to moles of NAOH (same moles required for neutralization reaction)

M1*V1=M2*V2

M1=7.48*10 -2M

V1=

M2=0.244M

V2=115ml=0.115L

(7.48*10 -2)*V1=0.244*0.115

V1=(0.244*0.115)/0.0748

V1=0.3751L=375ml

therefore volume of perchloric acid can be neutralized is 375ml