At 25 ∘C, the equilibrium partial pressures for the reaction
A(g)+2B(g)↽−−⇀C(g)+D(g)
were found to be ?A=5.74 atm, ?B=4.31 atm, ?C=4.20 atm, and ?D=4.67 atm.
What is the standard change in Gibbs free energy of this reaction at 25 ∘C? In kJ/mol.
Answer: —24.305 kJ/mol
Note: The value of Gibbs free energy change is negative. This signifies that the reaction or the process is spontaneous.
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