Question

What mass of sucrose, C12H22O11, would be needed to prepare 100. mL of 0.23 M C12H22O11?

Answer 1

volume , V = 100 mL

= 0.1 L

we have below equation to be used:

number of mol,

n = Molarity * Volume

= 0.23*0.1

= 2.3*10^-2 mol

Molar mass of C12H22O11 = 12*MM(C) + 22*MM(H) + 11*MM(O)

= 12*12.01 + 22*1.008 + 11*16.0

= 342.296 g/mol

we have below equation to be used:

mass of C12H22O11,

m = number of mol * molar mass

= 2.3*10^-2 mol * 342.296 g/mol

= 7.87 g

Answer: 7.87 g