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if a sample has an empirical formula of P203 but a molar mass of 219.9 g/...

if a sample has an empirical formula of P203 but a molar mass of 219.9 g/ mol ,what is the molecular formula

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Answer #1

emperical formula = P2O3

mass of emperical formula = 2x 31 + 3 x 16 = 110 g

molar mass = 219.9 g/mol

ratio = molar mass / emperical formula mass

        = 219.9 / 110

        = 2.00

Molecular formula = n x emperical formula

                              = 2 x P2O3

Molecular formula = P4O6

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