What is the standard free energy of the Ni/Zn cell (in kJ) if the standard voltage is .51
Zn(s) ----------------> Zn^2+ (aq) + 2e^- E0 = 0.76v
Ni^2+ (aq) + 2e^- -----------> Ni(s) E0 = -0.25v
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Zn(s) + Ni^2+ (aq) -------------> Zn^2+ (aq) + Ni(s) E0 cell = 0.51v
n = 2
G0 = -nE0cell *F
= -2*0.51*96500
= -98430J = -98.43KJ >>>>>answer
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