Question

Calculate the ratio of effusion rates for argon and neon gases. Use a ratio of Ar:Ne

1.19:1

1.41:1

0.711:1

0.505:1

Answer #1

ANSWER===>

Set rate_{1} = Ar = 1.19

Set rate_{2} = Ne = 1

The molecular weight of Ar = 39.94

The molecular weight of Ne = 20.18

Graham's Law is:

r_{1} over r_{2} = √MM_{2} over
√MM_{1 } mm1 ==> molar mass
argon, mm2 molar mass ==> argon

Substituting, we have:

1.19/ 1 = √(20.18 / 39.94)

= 0.710

ratio are 1.19/0.710*1 ===> 1.19/0.710

same procedure followed other respectevly result shown here as

1.41;1 ===>1.41/0.710

0.711====>0.711/0.710

0.505/1===>0.505/0.710

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