Calculate the ratio of effusion rates for argon and neon gases. Use a ratio of Ar:Ne
1.19:1
1.41:1
0.711:1
0.505:1
ANSWER===>
Set rate1 = Ar = 1.19
Set rate2 = Ne = 1
The molecular weight of Ar = 39.94
The molecular weight of Ne = 20.18
Graham's Law is:
r1 over r2 = √MM2 over √MM1 mm1 ==> molar mass argon, mm2 molar mass ==> argon
Substituting, we have:
1.19/ 1 = √(20.18 / 39.94)
= 0.710
ratio are 1.19/0.710*1 ===> 1.19/0.710
same procedure followed other respectevly result shown here as
1.41;1 ===>1.41/0.710
0.711====>0.711/0.710
0.505/1===>0.505/0.710
Get Answers For Free
Most questions answered within 1 hours.