Question

Ammonia reacts with oxygen according to the equation: 4NH3(g)+5O2(g)→4NO(g)+6H2O(g)ΔHrxn=−906kJ. Calculate the heat (in kJ) associated with...

Ammonia reacts with oxygen according to the equation: 4NH3(g)+5O2(g)→4NO(g)+6H2O(g)ΔHrxn=−906kJ. Calculate the heat (in kJ) associated with the complete reaction of 215 g of NH3.

Science   Chemistry   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

4NH3(g)+5O2(g)→4NO(g)+6H2O(g)        ΔHrxn=−906kJ.

negative values of ΔH indicate exothermic reactions. MW of ammonia is 17.

4 moles of NH3 on combustion produce 906 kl heat

68 gms (4x17) of NH3 on combustion produce 906 kl heat

215 gms of NH3 on combustion produce -------- kj heat

                                                           =(906/68)x 215= 2864.6 kj

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Ammonia reacts with oxygen according to the equation: 4NH3(g)+5O2(g)→4NO(g)+6H2O(g) ΔHrxn=-906 kJ Part A Calculate the heat...
Ammonia reacts with oxygen according to the equation: 4NH3(g)+5O2(g)→4NO(g)+6H2O(g) ΔHrxn=-906 kJ Part A Calculate the heat (in kJ) associated with the complete reaction of 284 g of NH3.
Consider the chemical equation. 4NH3+5O2⟶4NO+6H2O4NH3+5O2⟶4NO+6H2O When 26 g of ammonia burn in 26 g of oxygen,...
Consider the chemical equation. 4NH3+5O2⟶4NO+6H2O4NH3+5O2⟶4NO+6H2O When 26 g of ammonia burn in 26 g of oxygen, what is the limiting reagent? NH3NH3 and O2O2 NONO O2O2 H2OH2O NH3NH3
4NH3 + 5O2 --> 4NO + 6H2O 1. Nitric acid is made by first reacting ammonia...
4NH3 + 5O2 --> 4NO + 6H2O 1. Nitric acid is made by first reacting ammonia and oxygen to form nitric oxide: NH3 (g)+O2 (g)⟶NO(g)+H2O(g) Calculate the heat of reaction at a) standard conditions (this is what the book calls ∆ ) and b) at 500 °C. (This is what the book calls ∆ ) 2. (Builds off of problem 1). Ammonia gas enters a reactor with 30% more dry air (no water vapor) than is required for complete conversion....
Ammonia is burned to form nitric oxide in the following reaction: 4NH3 + 5O2 ----> 4NO...
Ammonia is burned to form nitric oxide in the following reaction: 4NH3 + 5O2 ----> 4NO + 6H2O The Fractional conversion of oxygen is 0.500 and the inlet flow rates of NH3 is 10 mol/h Oxygen is supplied using air (assume 79:21 - N2:O2) fed to reactor at rate of 710 g/h (a) How much oxygen is fed to the reactor (in mol/h)? (b) Which reactan is in excess and by how much (in %)? (c) Calculate the exit molar...
The gas phase equilibrium reaction is exothermic : 4NH3(g)+5O2(g) <----->4NO(g)+6H2O(g) What is the effect of each...
The gas phase equilibrium reaction is exothermic : 4NH3(g)+5O2(g) <----->4NO(g)+6H2O(g) What is the effect of each of the following? A) Decreasing the volume B) increasing/adding H2O C) increasing the temperature D) removing some oxygen E) increasing/adding NH3 F) adding a catalyst
From the following balanced equation, 4NH3(g)+5O2(g)⟶4NO(g)+6H2O(l) how many moles of H2O can be formed when 2.5mol...
From the following balanced equation, 4NH3(g)+5O2(g)⟶4NO(g)+6H2O(l) how many moles of H2O can be formed when 2.5mol NH3 react with 2.5mol O2?
Q1Calculate the delta H for N2 (g) + O2 (g)------>2NO(g) 4NH3(g) +5O2(g)--->4NO(g)+6H2O(l). DeltaH= -1170kJ 4NH3(g) +...
Q1Calculate the delta H for N2 (g) + O2 (g)------>2NO(g) 4NH3(g) +5O2(g)--->4NO(g)+6H2O(l). DeltaH= -1170kJ 4NH3(g) + 3O2(g)--->2N2(g)+6H2O(l) Delta H =-1530kJ Q2Calculate standard heat of formation delta H degree f. For NCl 3 NH3(g)+3HCl (g)--->NCl3(g)+3H2(g). Delta H =564.8kJ
Consider this reaction: 4NH3 + 5O2 --> 4NO + 6H2O If you start with 5.5 moles...
Consider this reaction: 4NH3 + 5O2 --> 4NO + 6H2O If you start with 5.5 moles of NH3 and 8 moles of O2, then: how many moles of NO can be formed? how many moles of H2O can be formed?
Nitrogen dioxide reacts with water to produce oxygen and ammonia:4NO2(g)+6H2O(g)→7O2(g)+4NH3(g) At a temperature of 415 ∘C...
Nitrogen dioxide reacts with water to produce oxygen and ammonia:4NO2(g)+6H2O(g)→7O2(g)+4NH3(g) At a temperature of 415 ∘C and a pressure of 725 mmHg , how many grams of NH3 can be produced when 4.10 L of NO2 react? Glucose, C6H12O6, is metabolized in living systems according to the reaction C6H12O6(s)+6O2(g)→6CO2(g)+6H2O(l) How many grams of water can be produced from the reaction of 24.5 g of glucose and 6.30 L of O2 at 1.00 atm and 37 ∘C?
4NH3 (g)+5O2 (g)-->4NO (g)+6H2O (g) What is the maximum mass of H2O that can be produced...
4NH3 (g)+5O2 (g)-->4NO (g)+6H2O (g) What is the maximum mass of H2O that can be produced by combining 78.0 G of each reactant?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT