Question

If 3.5 mL of distilled water is added to 1.5 mL of a 0.150 M solution...

If 3.5 mL of distilled water is added to 1.5 mL of a 0.150 M solution of CoCl2, What is the Kosan Traicion of the resulting solution?

Homework Answers

Answer #1

The new dilution value:

We need to apply dilution law, which is based on the mass conservation principle

initial mass = final mass

this apply for moles as weel ( if there is no reaction, which is the case )

mol of A initially = mol of A finally

or, for this case

moles of A in stock = moles of A in diluted solution

Recall that

mol of A = Molarity of A * Volume of A

then

moles of A in stock = moles of A in diluted solution

Molarity of A in stock * Volume of A in stock = Molarity of A in diluted solution* Volume of A in diluted solution

Now, substitute known data

M1*V1 = M2*V2

0.15*1.5 = M2*3.5

M2 = 0.15*1.5 /3.5 M

New molarity = 0.064285M

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