Question

How many chlorine atoms are in 6.51 mL of dichloromethane

Answer 1

volume of dichloromethane = 6.51 mL

Molar mass of dichloromethane = 84.93 g/mol

Density of dichloromethane = 1.3266 g/mL

So, mass of dichloromethane = density x volume

mass of dichloromethane = 1.3266 x 6.51

mass of dichloromethane = 8.636 g

Now, moles of dichloromethane = 8.636 / 84.93

= 0.1017 mole

[one molecule of dichloromethane (CH2Cl2) has two atoms of Cl]

As, 1 mole of dichloromethane contains 2 x 6.022×10²³ (Avogadro constant)= 12.044 x 10²³ atoms of Cl

then Cl atoms present in 0.1017 mole of dichloromethane = 0.1017 x 12.044 x 10²³ / 1

= 1.22 x 10²³ atoms of Cl