Question

The equilibrium constant (Kc) for the following reaction is 6.7 × 10–10 at 630 °C. N2(s)...

The equilibrium constant (Kc) for the following reaction is 6.7 × 10–10 at 630 °C. N2(s) + O2(g) 2 NO(g) What is the equilibrium constant for the reaction below at the same temperature? 1/2 N2(g) + 1/2 O2(g) NO(g)

a. 4.5 × 10−19

b. 3.4 × 10−10

c. 1.3 × 10−9

d. 1.8 × 10−5

e. 2.6 × 10−5

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Answer #2

answered by: anonymous
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