DDQ does not react directly with NaOH. Rather, it is the chlorine which may be released from it.
When chlorine reacts with cold solution of sodium hydroxide, the disproportionation goes to lower oxidation states:
Cl2 + 2KOH ⟶ KCl + KClO + H2O
with hot solution the oxidation state of chlorine goes up to +V:
3Cl2 + 6KOH ⟶ KClO3 + 5KCl + 3H2O
Higher temperature promotes the formation of hypochlorous acid through hydrolysis of hypochlorite and so, quickens up the reaction.
Get Answers For Free
Most questions answered within 1 hours.