Question

Zn + HCl --> 2ZnCl2 + H2

Assuming you start with 10.0 g of zinc and 10.0 g hydrochloric acid, identify the limiting reagent and determine what mass of the other reagent will remain after the reaction runs to completion.

Answer 1

you have given reaction is wrong the correct reaction is

Zn + 2HCl ZnCl₂ + H₂

molar mass of Zn = 65.38 gm/mole that mean 1 mole of Zn = 65.38 gm Zn

molar mass of HCl =36.4609gm/mol that mean 1 mole of HCl =36.4609gm mol then 2 mole HCl = 72.9218 gm

According to reaction 1 mole of Zn react with 2 mole of HCl that mean 65.38 gm of Zn require 72.9218 gm of HCl

then 10 gm of Zn require 72.921810/65.38 = 11.15 gm of HCl

but HCl taken only 10 gm threfore HCl is limiting reagent

for 72.9218 gm of HCl require 65.38 gm of Zn then 10 gm of HCl require 1065.38/729218 =.8.96 gm of Zn

we taken 10 gm of Zn thus 10 - 8.96 = 1.04 gm of Zn remain after reaction runs to completion.