Question

# Zn + HCl --> 2ZnCl2 + H2 Assuming you start with 10.0 g of zinc and...

Zn + HCl --> 2ZnCl2 + H2

Assuming you start with 10.0 g of zinc and 10.0 g hydrochloric acid, identify the limiting reagent and determine what mass of the other reagent will remain after the reaction runs to completion.

you have given reaction is wrong the correct reaction is

Zn + 2HCl ZnCl2 + H2

molar mass of Zn = 65.38 gm/mole that mean 1 mole of Zn = 65.38 gm Zn

molar mass of HCl =36.4609gm/mol that mean 1 mole of HCl =36.4609gm mol then 2 mole HCl = 72.9218 gm

According to reaction 1 mole of Zn react with 2 mole of HCl that mean 65.38 gm of Zn require 72.9218 gm of HCl

then 10 gm of Zn require 72.9218 10/65.38 = 11.15 gm of HCl

but HCl taken only 10 gm threfore HCl is limiting reagent

for 72.9218 gm of HCl require 65.38 gm of Zn then 10 gm of HCl require 10 65.38/729218 =.8.96 gm of Zn

we taken 10 gm of Zn thus 10 - 8.96 = 1.04 gm of Zn remain after reaction runs to completion.

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