How many grams of H2(g) can theoretically be produced from a 5-g sample of magnesium metal and excess HCl(aq)?
Molar mass of Mg = 24.31 g/mol
mass of Mg = 5 g
mol of Mg = (mass)/(molar mass)
= 5/24.31
= 0.2057 mol
we have the Balanced chemical equation as:
Mg + 2 HCl —> MgCl2 + H2
From balanced chemical reaction, we see that
when 1 mol of Mg reacts, 1 mol of H2 is formed
mol of H2 formed = moles of Mg
= 0.2057 mol
Molar mass of H2 = 2.016 g/mol
mass of H2 = number of mol * molar mass
= 0.2057*2.016
= 0.415 g
Answer: 0.415 g
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