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what volume of .20 M glucose solution can be prepared from 25 g of glucose?

what volume of .20 M glucose solution can be prepared from 25 g of glucose?

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Answer #1

Molar mass of C6H12O6 = 6*MM(C) + 12*MM(H) + 6*MM(O)

= 6*12.01 + 12*1.008 + 6*16.0

= 180.156 g/mol

mass of C6H12O6 = 25 g

we have below equation to be used:

number of mol of C6H12O6,

n = mass of C6H12O6/molar mass of C6H12O6

=(25.0 g)/(180.156 g/mol)

= 0.1388 mol

we have below equation to be used:

M = number of mol / volume in L

0.20 = 0.1388/ volume in L

volume = 0.6938 L

volume = 694 mL

Answer: 694 mL

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