When solutions of (NH4)2SO4 and Ba(NO3)2 are mixed, a precipitate of BaSO4 forms, leaving soluble NH4NO3 in the solution. Write the ionic equation for the reaction.
The actual balanced molecular reaction would be,
(NH4)2SO4 (aq) +
Ba(NO3)2 (aq) -------->
BaSO4 (s) + 2 NH4NO3 (aq)
First write the total ionic equation and do not split the insoluble
solids
2NH4+ (aq) +SO42-
(aq)+Ba2+ (aq)+2NO3- (aq)
-----> BaSO4
(s)+2NH4+(aq)+2NO3-
(aq)
cancel out the similar terms on both the sides of the equation i.e)
spectator ions and write the final
equation.
Therefore the net ionic equation is,
Ba2+ (aq) + SO42- (aq)
--------> BaSO4 (s)
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