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Enter your answer in the provided box. What is the emf of a cell consisting of...

Enter your answer in the provided box.

What is the emf of a cell consisting of a Pb2+ / Pb half-cell and a Pt / H+ / H2 half-cell if [Pb2+] = 0.78 M, [H+] = 0.079 M and PH2 = 1.0 atm ?
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Answer #1

Step 1 : Write the overall reaction.

Step 2 : Calculate the E°cell

Step 3 : Use Nernst equation at 298 K ( as no temperature is mentioned ). Put Q, E°cell and n. n is no of electrons transferred, here it is 2. Then just calculate emf value.

Answer : Ecell = emf = 0.064 V

** If you don't understand, comment below. The answer may vary a bit, but the process is absolutely fine.

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