Question

Age (x) (years) Number Surviving (nx) Proportion Surviving (lx) log(nx) Fecundity (fx) lx fx x lx...

Age (x) (years)

Number Surviving (nx)

Proportion Surviving (lx)

log(nx)

Fecundity (fx)

lx fx

x lx fx

0

80,000

1.0

0

0

0

1

750

0.009375

0.1

0.0009375

0.0009375

2

400

0.005

2

0.01

0.02

3

320

0.004

80

0.32

0.96

4

240

0.003

120

0.36

1.44

5

80

0.001

160

0.16

0.8

calculate the lognx, and this is the answer from our professor:

Age (x) (years)

Number Surviving (nx)

Proportion Surviving (lx)

log(nx)

Fecundity (fx)

0

80,000

1.0

3.0

0

1

750

0.009

0.972

0.1

2

400

0.005

0.699

2

3

320

0.004

0.602

80

4

240

0.003

0.477

120

5

80

0.001

0.000

160

Why??? log (80,000)=4.903, why his answer is 3.0????

Homework Answers

Answer #1

For age = 5 years,

Log (80) = 1.903

But it is written 0.000

Actually from all the log(nx) values, 1.903 is subtracted.

For example, for age = 0 years, log (80000) = 4.903

log 80000 - 1.903 = 3.0

Similar is the case for all the ages.

The professor has subtracted 1.903 from each answer. Normally, this is done because it is easy to compare the results with relative to each other. If we keep the original values, then it becomes difficult to compare them. We make one value as zero, and compare the rest with that value.

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