Perform the following calculations involving concentrations of iodate ions.
(a) The iodate ion concentration of a saturated solution of Ce(IO3)4 was found to be 7.35 ✕ 10−4 mol/L. Find the Ksp.
(b) Find the concentration (in M) of iodate ions in a saturated solution of Ca(IO3)2. (Ksp = 6.47 ✕ 10−6)
a)
4s = 7.35*10^-4
s = 1.84*10^-4
The salt dissolves as:
Ce(IO3)4 <----> Ce4+ + 4 IO3-
s 4s
[IO3-] = 7.35*10^-4
So,
4s = 7.35*10^-4
s = 1.84*10^-4
Ksp = [Ce4+][IO3-]^4
Ksp = (s)*(4s)^4
Ksp = 256(s)^5
Ksp = 256(1.84*10^-4)^5
Ksp = 5.40*10^-17
Answer: 5.40*10^-17
b)
The salt dissolves as:
Ca(IO3)2 <----> Ca2+ + 2 IO3-
s 2s
Ksp = [Ca2+][IO3-]^2
6.47*10^-6=(s)*(2s)^2
6.47*10^-6= 4(s)^3
s = 1.174*10^-2 M
[IO3-] = 2s
= 2*1.174*10^-2 M
= 2.35*10^-2 M
Answer: 2.35*10^-2 M
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