How much 0.20M NaCl solution would you need to prepare 250 mL of a 0.15 M solution?
use dilution formula
M1*V1 = M2*V2
Here:
M1 is molarity of solution before dilution
M2 is molarity of solution after dilution
V1 is volume of solution before dilution
V2 is volume of solution after dilution
we have:
M1 = 0.2 M
M2 = 0.15 M
V2 = 250.0 mL
we have below equation to be used:
M1*V1 = M2*V2
V1 = (M2 * V2) / M1
V1 = (0.15*250)/0.2
V1 = 187.5 mL
Answer: 187.5 mL
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