Question

a) Write the balanced dissociation equation for MgCl2. b) In 300.0 mL of a 0.50 M...

a) Write the balanced dissociation equation for MgCl2.

b) In 300.0 mL of a 0.50 M MgCl2 solution, what would be the concentration of the chloride ions? (2marks)

c) If water is added to a 25.0 mL sample of 2.70 g/L NaOH(aq) until the volume becomes 4.00 L, find the concentration of the final solution in mol/L.

Homework Answers

Answer #1

Hope this will help u...

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
255 ml of a 0.15 M MgCl2 (aq) solution is mixed with 125 ml of a...
255 ml of a 0.15 M MgCl2 (aq) solution is mixed with 125 ml of a 0.50 M NaCl(aq) solution. Determine the molarity of chloride ions in the resulting solution.
Suppose that 300.0 mL of 1.00 M HCl at 25.0°C is added to 300.0 mL of...
Suppose that 300.0 mL of 1.00 M HCl at 25.0°C is added to 300.0 mL of 1.00 M NaOH at 25.0°C in a coffee cup calorimeter. If the enthalpy of the reaction is −54.0 kJ/mol of NaCl formed, what is the final temperature of the solution in the calorimeter? Assume the mixture has a specific heat capacity of 4.18 J/(g·K) and a density of 1.00 g/mL (1) 3.5°C                     (2) 6.5°C                     (3) 18.5°C                   (4) 31.5°C                   (5) 46.5°C
HCl (aq) + NaOH (aq) --> H2O (l) + NaCl (aq) 4.00 mL of an unknown...
HCl (aq) + NaOH (aq) --> H2O (l) + NaCl (aq) 4.00 mL of an unknown acid solution containing HCl was added to flask containing 30.00 mL of deionized water and two drops of an indicator. The solution was mixed and then titrated with NaOH until the end point was reached. Use the following titration data to determine the mass percent of HCl in the acid solution. Mass of flask: 125.59 g Mass of flask + acid solution: 129.50 g...
Quick Solve Please 2.        15.0 mL of 0.50 M NaOH is added to a 100.-mL sample...
Quick Solve Please 2.        15.0 mL of 0.50 M NaOH is added to a 100.-mL sample of 0.442 M NH3 (Kb for NH3 = 1.8 ´ 10–5). What is the equilibrium concentration of NH4+ ions? (3%) 3.        What is the percent dissociation of HNO2 when 0.074 g of sodium nitrite is added to 115.0 mL of a 0.068 M HNO2 solution? Ka for HNO2 is 4.0 × 10–4. (4%)
A.) Write the balanced equation for the hydration of CuSO4. Indicate the physical states using the...
A.) Write the balanced equation for the hydration of CuSO4. Indicate the physical states using the abbreviations (s), (l), or (g) for solid, liquid, or gas, respectively. Use (aq) to indicate the aqueous phase. Indicate appropriate charges on negative and positive ions if they are formed. Express your answer as a complete chemical equation including all phases. Do not include water in your answer. B.) A sample solution containing sulfate ions (SO42−) was analyzed and was found to contain 3.5...
please answer these questions 1-Consider the following balanced equation: 2 Fe(s) + 3 Cl2(g) → 2...
please answer these questions 1-Consider the following balanced equation: 2 Fe(s) + 3 Cl2(g) → 2 FeCl3(s) How many moles of iron(III) chloride are obtained when 7.67 moles of chlorine gas react with excess solid iron? Assume the reaction is 100% efficient. 2- What mass of hydrochloric acid must have reacted with magnesium if 9.56 grams of hydrogen were produced? Include units with your answer. The UNBALANCED equation is provided: Mg(s) + HCl(aq) → H2(g) + MgCl2(aq) 3- What volume...
A buffer is made by adding 0.300 mol of CH3COOH and 0.300 mol of CH3COONa to...
A buffer is made by adding 0.300 mol of CH3COOH and 0.300 mol of CH3COONa to enough water to make 1.000 L of solution. The pH of the buffer is 4.74. (a) Calculate the pH of this solution after 5.00 mL of 4.0 M NaOH (aq) solution is added. Write out the balanced equation for the reaction. (b) For a comparison, calculate the pH of a solution made by adding 5.0 mL of 4.0 M NaOH (aq) solution to 1.000...
Water Hardness Lab follow up Questions Trial Initial EDTA Volume (mL) Final EDTA Volume (mL) Total...
Water Hardness Lab follow up Questions Trial Initial EDTA Volume (mL) Final EDTA Volume (mL) Total Volume of EDTA Used (mL) 1 8.5 6 2.5 2 5.0 3.0 2.0 3 3.0 0.5 2.3 Average Volume of EDTA Used (mL): 2.3 Average Volume of EDTA Used (mL) Concentration Ca2+ Ions Per Liter of Water (mol/L) Water Hardness (ppm CaCO3) 2.3 0.0023 230 2.Approximately how much calcium would you ingest by drinking six, 8-oz glasses of your local water? Hint: 1 oz...
Sodium oxide, Na2O, reacts with water to give NaOH. A. Write a balanced equation for the...
Sodium oxide, Na2O, reacts with water to give NaOH. A. Write a balanced equation for the reaction. B. What is the pH of the solution prepared by allowing 1.45 g of Na2O to react with 350.0 mL of water? Assume that there is no volume change. C. How many milliliters of 0.0100 M HCl are needed to neutralize the NaOH solution prepared in the part B?
a Solution is prepared by diluting 450 mL of 0.773 M cobalt(11) chloride solution with water...
a Solution is prepared by diluting 450 mL of 0.773 M cobalt(11) chloride solution with water to a final volume of 1.25 L. a) calculate the molarities of cobalt (II) and chloride ions in this solution b) determine the mass of cobalt (II) chloride that was dissolved to give the original solution
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT