What is the standard molar entropy for calcium hydroxide, Ca(OH)2?
Express your answer in units of J/mol*K
What is the entropy of 4.06 g of Ca(OH)2?
Express your answer in units of J/K
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The standard molar entropy for calcium hydroxide, Ca(OH)2 = 83.4 J/(mol K).
given-
4.06 g of Ca(OH)2
molecular weight of Ca(OH)2- 40+32+2 = 74 g/mol
moles of Ca(OH)2= 4.06/74
= 0.05 moles
Hence entropy of 4.06 g of Ca(OH)2 = 0.05 mol X 83.4 J/(mol K).
= 4.17 J/K
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